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Published online by Cambridge University Press: 06 February 2018
If $3\leqslant n<\unicode[STIX]{x1D714}$ and
$V$ is a vector space over
$\mathbb{Q}$ with
$|V|\leqslant \aleph _{n-2}$, then there is a well ordering of
$V$ such that every vector is the last element of only finitely many length-
$n$ arithmetic progressions (
$n$-APs). This implies that there is a set mapping
$f:V\rightarrow [V]^{{<}\unicode[STIX]{x1D714}}$ with no free set which is an
$n$-AP. If, however,
$|V|\geqslant \aleph _{n-1}$, then for every set mapping
$f:V\rightarrow [V]^{{<}\unicode[STIX]{x1D714}}$ there is a free set which is an
$n$-AP.