No CrossRef data available.
Published online by Cambridge University Press: 20 November 2018
In this note we prove the following surprising characterization: if $X\,\subset \,{{\mathbb{A}}^{n}}$ is an (embedded, non-empty, proper) algebraic variety deûned over a field
$k$ of characteristic zero, then
$X$ is a hypersurface if and only if the module
${{T}_{{{O}_{{{\mathbb{A}}^{n\,/k}}}}}}(X)$ of logarithmic vector fields of
$X$ is a reflexive
${{O}_{{{\mathbb{A}}^{n}}}}$-module. As a consequence of this result, we derive that if
${{T}_{{{O}_{{{\mathbb{A}}^{n\,/k}}}}}}(X)$ is a free
${{O}_{{{\mathbb{A}}^{n}}}}$-module, which is shown to be equivalent to the freeness of the
$t$-th exterior power of
${{T}_{{{O}_{{{\mathbb{A}}^{n\,/k}}}}}}(X)$ for some (in fact, any)
$t\,\le \,n$, then necessarily
$X$ is a Saito free divisor.